List layers in directory .Net ArcObjects or plain .Net - C# preferably

List layers in directory .Net ArcObjects or plain .Net - C# preferably

Any code samples to list arcgis layer files from a directory so they can be looped over?

Using a windows form, button, and listbox you could use this:

Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Try ' make a reference to a directory Dim di As New IO.DirectoryInfo("c:	emp") Dim diar1 As IO.FileInfo() = di.GetFiles("*.lyr*") Dim dra As IO.FileInfo 'list the names of all files in the specified directory For Each dra In diar1 ListBox1.Items.Add(dra.Name) Next Catch ex As Exception MessageBox.Show("Error " & ex.ToString) End Try End Sub

This should be easy to convert to C#, it is still .NET. Make sure to mark what artwork posted as the answer if it gives you the expected results.

try { DirectoryInfo di = new DirectoryInfo(@"c:	emp"); FileInfo diar1 = new di.GetFiles("*.lyr*"); foreach(FileInfo dra in diar1) { ListBox1.Items.Add(dra.Name); } } catch(Exception ex) { //do something with exception }

The following function goes through a directory, gets a list of all the XML files, sorts the list by name, then writes the filenames of the XML files out to a text file. It does a little more than you need, but the principal is there of looping through the directory and doing something with the files - just another way to go about it.

public static void make_enerdeq_filelist(Constants c) // Create Enerdeq_Filelist.txt to feed our ETL job { // Kill Enerdeq_Filelist.txt if it exists if (File.Exists(c.infaServer + c.fileList)) { File.Delete(c.infaServer + c.fileList); } // Sort files by name-alpha, INFA wants sorted input DirectoryInfo dir = new DirectoryInfo(c.infaServer); StreamWriter sw = File.CreateText(c.infaServer + c.fileList); string[] xml_files = Directory.GetFiles(c.infaServer); IComparer comp = new FileComparer(FileComparer.CompareBy.Name); Array.Sort(xml_files, comp); foreach (string xml_file in xml_files) { FileInfo fi = new FileInfo(xml_file); string file_name = fi.Name; if (file_name.EndsWith(".xml")) // XML files only { sw.WriteLine(file_name); sw.Flush(); } } sw.Close(); }